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Differentials






Separating dy and dx


The derivative dydx\frac{dy}{dx} is defined as a limit—a single object, not a fraction. But Leibniz notation invites the question: can dydy and dxdx stand on their own? Differentials answer yes, with precise meaning. The symbol dxdx represents an independent small change in xx, and dy=f′(x) dxdy = f'(x)\,dx represents the corresponding change in yy predicted by the tangent line.

This formalism does more than justify notation. It provides a direct tool for approximating function values near a known point, estimating how errors in measurement propagate through calculations, and explaining why Leibniz notation behaves like fraction arithmetic in the chain rule and in integration.

Key Terms

Differential— dxdx is a free increment; dy=f′(x)⋅dxdy = f'(x) \cdot dx is the tangent-line response
Derivative— dy/dxdy/dx separated into two independent quantities
Partial Derivative— extends differentials to functions of several variables
Tangent Line— the differential dydy follows the tangent line, not the curve

See All Calculus Definitions →


The Differential dx


The differential dxdx is an independent variable. It represents a change in xx—an increment away from a given value. Unlike the hh or Δx\Delta x in the limit definition, dxdx is not required to approach zero. It is a finite quantity that can be positive, negative, or zero.

There is no formula for dxdx—it is chosen freely. Choosing dx=0.1dx = 0.1 means considering what happens when xx shifts by 0.10.1. Choosing dx=−2dx = -2 means shifting xx by −2-2. The differential dxdx sets the scale for the approximation that follows.

The notation is consistent with Leibniz notation for the derivative. When dy/dxdy/dx is treated as a ratio of differentials rather than a limit symbol, the algebraic manipulations that make Leibniz notation powerful—cancellation in the chain rule, separation in differential equations—become formally valid rather than merely suggestive.

The Differential dy


Given y=f(x)y = f(x) where ff is differentiable, the differential of yy is defined as

Differential
dy=f′(x) dxdy = f'(x)\, dx
Learn more about this formula: Differential →


The differential dydy depends on two things: the point xx (which determines the slope f′(x)f'(x)) and the increment dxdx (which determines the scale). For fixed xx, dydy is a linear function of dxdx—doubling dxdx doubles dydy.

Pitfall: Dropping the dx
Writing dy=3x2dy = 3x^2 for y=x3y = x^3 leaves out dxdx and gives dy=12dy = 12 at x=2x = 2 for any step. With dx=0.1dx = 0.1, dy=3(2)2(0.1)=1.2dy = 3(2)^2(0.1) = 1.2, close to the actual Δy=1.261\Delta y = 1.261.

Geometrically, dydy is the vertical change along the tangent line at xx when the horizontal position shifts by dxdx. The tangent line rises (or falls) at rate f′(x)f'(x), so a horizontal shift of dxdx produces a vertical shift of f′(x)⋅dxf'(x) \cdot dx.

RULE
For a linear function f(x)=mx+bf(x) = mx + b, the differential dy=m⋅dxdy = m \cdot dx equals the actual change in ff exactly, because the tangent line to a linear function is the function itself.

For nonlinear functions, dydy is an approximation—exact in the limit as dx→0dx \to 0, and increasingly approximate as dxdx grows.

dy Versus Δy


Two quantities measure the change in yy when xx changes by dxdx:

dy Versus Δy
Δy=f(x+dx)−f(x)(actual change)\Delta y = f(x + dx) - f(x) \qquad \text{(actual change)}

dy Versus Δy
dy=f′(x)⋅dx(tangent line estimate)dy = f'(x) \cdot dx \qquad \text{(tangent line estimate)}

The actual change Δy\Delta y follows the curve. The differential dydy follows the tangent line. The difference Δy−dy\Delta y - dy is the error introduced by the linear approximation.

THEOREM
For small dxdx, the error Δy−dy\Delta y - dy is much smaller than dxdx itself. Precisely, lim⁡dx→0Δy−dydx=0\lim_{dx \to 0} \frac{\Delta y - dy}{dx} = 0—the error shrinks faster than the increment.

This is what makes the tangent line a good approximation near the point of tangency.

For larger dxdx, the gap between Δy\Delta y and dydy widens. The tangent line is a local tool: reliable near xx, increasingly unreliable far from it. The curvature of ff—governed by the second derivative—determines how quickly the approximation deteriorates.
f(x) = x^2 from x = 1 with dx = 1: the tangent rises dy = 2, the curve rises delta y = 3, the gap is 1xy123−112345dx = 1tangent at x = 1y = x²Δy = 3 (curve)error 1dy = 2 (tangent)dy follows the tangent, Δy follows the curve; the gap is the error
dy and Δy side by side

f(x) = x² at x = 1 with dx = 1. Along the tangent line, whose slope is f′(1) = 2, the run of 1 produces a rise of dy = 2 (navy column). Along the curve, the same run produces Δy = f(2) − f(1) = 3 (blue column). The amber piece on top is the difference Δy − dy = 1, the error of the tangent-line estimate. A smaller dx would shrink the error much faster than it shrinks dx.

For f(x) = x² the error is exactly (dx)²: halve dx and the error drops to a quarter.
Aspect dy (tangent line) Δy (actual curve)
Definition dy = f'(x) · dx Δy = f(x + dx) − f(x)
Geometric meaning vertical change along the tangent line vertical change along the curve itself
Computation one slope evaluation × increment requires evaluating f at two points
Small dx behavior accurate estimate of Δy nearly equal to dy; error shrinks faster than dx
Large dx behavior drifts away from Δy; error scales with f''(x)·(dx)² diverges from dy as curvature accumulates
Typical use quick approximation, error propagation exact change when both function values are known

Differential Notation

Notation

Differential Notation

Four marks, and the whole subject turns on telling two pairs apart: dd from Δ\Delta, and dydy from Δy\Delta y.
dydx\frac{dy}{dx} as a derivative belongs to Derivatives. Here it is re-read as an actual quotient.
Δx\Delta x · Δy\Delta y
delta x, delta y
Actual change. Δx=x2−x1\Delta x = x_2 - x_1, and Δy=f(x+Δx)−f(x)\Delta y = f(x + \Delta x) - f(x) is what the function really does over that step. Exact, no approximation. Capital delta only — the keyboard has Δ\Delta under Greek letters.
CasesΔ\Delta shrinking toward zero is the whole content of the limit definition of the derivative. In numerical work it stays finite and is the step size.
Also writtenhh for Δx\Delta x in limit definitions, where the delta is cumbersome inside a fraction.
Do not confuseLowercase δ\delta is not this. It is the tolerance in an epsilon-delta argument, or a variation in the calculus of variations — a quantity you choose, not a change you measure.
dxdx
dee x
The differential of the independent variable — an increment you assign. dx=Δxdx = \Delta x exactly, by definition. It is not infinitely small, and nothing here requires it to be.
CasesWritten large in error estimation, tiny in approximation, symbolic under an integral sign. Same object each time; only the size of the number changes.
Also written∂x\partial x once other variables are held fixed.
Do not confuseThe dd is not a factor multiplying xx, and dxdx is not "d times x". It is one symbol. The substitution rule in integration manipulates it algebraically, which is what makes the reading tempting and wrong.
Same glyph elsewhereThe same dd opens ddx\frac{d}{dx} as an operator on higher-order derivatives, where it is not a quantity at all.
dydy
dee y
The differential of the dependent variable: dy=f′(x) dxdy = f'(x)\,dx. Not the actual change in yy — the change predicted by the tangent line. It is defined, never measured.
CasesOn a curve, dy≠Δydy \neq \Delta y and the gap is the approximation error. On a straight line they are equal for every step size, which is the only case where the distinction disappears.
Also writtendfdf when the function is named rather than its output.
Do not confuseΔy\Delta y is what happened; dydy is what the tangent predicted. The section above measures the gap. Treating them as interchangeable is the commonest error with differentials, and it silently discards the entire error term.
dydx\frac{dy}{dx}
dee y by dee x
Everywhere else this is one indivisible symbol. Here, and only here, it is a genuine quotient of two defined quantities — which is what licenses the algebra in the chain rule and in separation of variables.
CasesDivide dy=f′(x) dxdy = f'(x)\,dx through by dxdx and the derivative falls out. That step is legitimate on this page and illegitimate on Derivatives, where dydy and dxdx have not been defined as objects.
Also writtendf/dxdf/dx, ddxf\frac{d}{dx}f — the operator form, which deliberately breaks the quotient reading.
Do not confuseThe permission is local. d2ydx2\frac{d^2y}{dx^2} is not a quotient of d2yd^2y and dx2dx^2 — second-order differentials do not cancel the way first-order ones do, and the notation gives no warning.
-2-112-110xycP = (c, f(c))slope = 1.89
The tangent line at P is the linear approximation

Near the marked point the curve and its tangent line are nearly indistinguishable, and the line’s slope, 1.89, is the f′(a) of the formula: moving dx along the line raises it by 1.89 dx, which is dy. The gap between line and curve, visible only farther out, is the error the differential ignores. Move the point and watch the approximating line follow on the tangent line at a point tool.

Linear approximation is therefore nothing more than reading the tangent line instead of the curve.

Linear Approximation


The differential formula rearranges into an approximation for function values:

Linear Approximation
f(x)≈f(a)+f′(a)(x−a)Δy≈f′(a) Δxf(x) \approx f(a) + f'(a)(x - a) \qquad \Delta y \approx f'(a)\, \Delta x
Learn more about this formula: Linear Approximation →


This is the linearization of ff at aa. Given a known value f(a)f(a) and the slope f′(a)f'(a), the tangent line estimates ff at nearby points.

To approximate 4.03\sqrt{4.03}: take f(x)=xf(x) = \sqrt{x}, x=4x = 4, dx=0.03dx = 0.03. Then f(4)=2f(4) = 2 and f′(x)=12xf'(x) = \frac{1}{2\sqrt{x}}, so f′(4)=14f'(4) = \frac{1}{4}. The estimate is 2+14(0.03)=2.00752 + \frac{1}{4}(0.03) = 2.0075. The actual value is 4.03≈2.00749...\sqrt{4.03} \approx 2.00749...—the approximation agrees to four decimal places, with an error of about 0.0000140.000014.

Pitfall: Reporting the change as the value
Stopping at dy=14(0.03)=0.0075dy = \frac{1}{4}(0.03) = 0.0075 gives only the change in ff, not 4.03\sqrt{4.03}. The estimate adds the known value: f(4)+dy=2+0.0075=2.0075f(4) + dy = 2 + 0.0075 = 2.0075.

The linearization can also be written as L(x)=f(a)+f′(a)(x−a)L(x) = f(a) + f'(a)(x - a), the tangent line at x=ax = a used as a function. For xx near aa, L(x)≈f(x)L(x) \approx f(x). The quality of the approximation depends on two factors: the size of ∣x−a∣|x - a| and the magnitude of f′′f'' near aa, which controls how quickly the curve diverges from its tangent.

Near a known point, the tangent line turns a hard function value into one multiplication and one addition.

Error Estimation


If a quantity xx is measured with error dxdx, the computed value f(x)f(x) inherits an error approximately equal to the differential:

Error Estimation
absolute error in f≈∣dy∣=∣f′(x)∣⋅∣dx∣\text{absolute error in } f \approx |dy| = |f'(x)| \cdot |dx|

Fact: Kepler's barrels sat at the maximum
In 1615 Kepler found that Austrian wine barrels were built close to the shape that holds the most wine for a given diagonal rod measurement. Near that maximum the volume barely responds to the shape: a barrel 10% off in its height-to-diameter ratio holds less than 1% less wine.

The derivative acts as an error amplification factor. Where ∣f′(x)∣|f'(x)| is large, small measurement errors in xx produce large errors in f(x)f(x). Where ∣f′(x)∣|f'(x)| is small, errors are suppressed.

The extreme case is a point where f′(x)=0f'(x) = 0, such as the top of a maximum. There the differential predicts no change at all: to first order, an error in xx does not reach f(x)f(x). The change that remains is proportional to (dx)2(dx)^2, far smaller than dxdx itself when dxdx is small.

The relative error normalizes by the function value:

Error Estimation
relative error in f≈∣dy∣∣f(x)∣=∣f′(x)∣∣f(x)∣⋅∣dx∣\text{relative error in } f \approx \frac{|dy|}{|f(x)|} = \frac{|f'(x)|}{|f(x)|} \cdot |dx|

The ratio f′(x)f(x)=ddx[ln⁡∣f(x)∣]\frac{f'(x)}{f(x)} = \frac{d}{dx}[\ln|f(x)|] is the logarithmic derivative. Relative error in the output is approximately the absolute value of the logarithmic derivative times the absolute error in the input.

Logarithmic Derivative
ddx[ln⁡f(x)]=f′(x)f(x)\frac{d}{dx}[\ln f(x)] = \frac{f'(x)}{f(x)}
Learn more about this formula: Logarithmic Derivative →


For f(x)=xnf(x) = x^n: f′(x)f(x)=nx\frac{f'(x)}{f(x)} = \frac{n}{x}, so the relative error in xnx^n is ∣n∣|n| times the relative error in xx. Squaring a measurement doubles its relative error. Cubing triples it. This scaling rule is a standard tool in experimental science for propagating uncertainties through power-law relationships.

Pitfall: Doubling the absolute error
For x=10±0.1x = 10 \pm 0.1, taking the error in x2x^2 as 2(0.1)=0.22(0.1) = 0.2 applies the rule to the wrong error. The rule doubles the relative error, from 1% to 2%, so ∣dy∣=2(10)(0.1)=2|dy| = 2(10)(0.1) = 2 and x2=100±2x^2 = 100 \pm 2.

In practice the rule is applied in three steps. A measured value comes with an absolute uncertainty, a ±\pm figure such as ±0.1\pm 0.1, and dividing it by the value turns it into a relative error. The rule scales that relative error by ∣n∣|n|, and multiplying the result by the computed value xnx^n turns it back into a ±\pm figure for the output. For a cube, n=3n = 3, and the same steps give the uncertainty in a volume computed from a measured edge.

The derivative is the exchange rate between input error and output error; for a power, relative errors scale by the exponent.

Differentials of Multiple Variables


When a formula involves several measured quantities, each contributes to the total error. If z=f(x,y)z = f(x, y), the total differential is

Total Differential
dz=∂z∂x dx+∂z∂y dydz = \frac{\partial z}{\partial x}\, dx + \frac{\partial z}{\partial y}\, dy
Learn more about this formula: Total Differential →


Each partial derivative weights the contribution of the corresponding variable's error. The total differential estimates how zz responds to simultaneous small changes in all inputs.

For the area of a rectangle A=lwA = lw: dA=w dl+l dwdA = w\,dl + l\,dw. If l=10±0.1l = 10 \pm 0.1 and w=5±0.05w = 5 \pm 0.05, then dA=5(0.1)+10(0.05)=1.0dA = 5(0.1) + 10(0.05) = 1.0. The area is approximately 50±1.050 \pm 1.0.

Pitfall: Adding the input errors unweighted
Adding the errors directly gives dA=0.1+0.05=0.15dA = 0.1 + 0.05 = 0.15 and A≈50±0.15A \approx 50 \pm 0.15. Each error has to be multiplied by its partial derivative: dA=5(0.1)+10(0.05)=1.0dA = 5(0.1) + 10(0.05) = 1.0, so A≈50±1.0A \approx 50 \pm 1.0.

For the volume of a cylinder V=πr2hV = \pi r^2 h: dV=2πrh dr+πr2 dhdV = 2\pi r h\,dr + \pi r^2\,dh. The radius error is amplified by 2πrh2\pi r h and the height error by πr2\pi r^2. Since rr enters as a square, its error contributes more heavily—consistent with the power-law scaling of relative error.

This extension uses partial derivatives, which generalize the single-variable derivative to functions of several variables. The total differential remains a linear approximation, now in multiple dimensions.

Differentials and Leibniz Notation


Differentials retroactively justify the algebraic behavior of Leibniz notation.

The chain rule states dydx=dydu⋅dudx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}. In differential form: dy=dydu dudy = \frac{dy}{du}\,du and du=dudx dxdu = \frac{du}{dx}\,dx. Substituting the second into the first gives dy=dydu⋅dudx dxdy = \frac{dy}{du} \cdot \frac{du}{dx}\,dx, which is dy=dydx dxdy = \frac{dy}{dx}\,dx. The intermediate variable dudu cancels as though these were fractions—and with differentials, they are.

Integration notation ∫f(x) dx\int f(x)\,dx also uses the differential dxdx meaningfully. The substitution rule u=g(x)u = g(x), du=g′(x) dxdu = g'(x)\,dx replaces dxdx with an expression involving dudu—a literal change of variable in the differential. The notation is not merely symbolic; it reflects the algebraic structure of differentials.

Separation of variables in differential equations—writing dydx=g(x)h(y)\frac{dy}{dx} = g(x)h(y) as dyh(y)=g(x) dx\frac{dy}{h(y)} = g(x)\,dx and integrating both sides—depends on treating dydy and dxdx as independent objects that can be rearranged. Differentials make this manipulation rigorous rather than heuristic.

See All Calculus Symbols and Notations →

Operation Differential manipulation What it justifies
Chain rule dy = (dy/du) du and du = (du/dx) dx → dy = (dy/du)(du/dx) dx du cancels algebraically, not merely suggestively
Substitution in integration u = g(x), du = g'(x) dx — replace dx in the integrand ∫f(x)dx is a literal change of variable, not symbolic shorthand
Separation of variables dy/dx = g(x)h(y) → dy/h(y) = g(x) dx, integrate both sides rearranging dy and dx as independent objects is rigorous
With differentials defined, the fraction-like moves of Leibniz notation are genuine algebra, not lucky shorthand.

Higher-Order Differentials


If dxdx is held constant (treated as a fixed increment), the second differential of yy is

Higher-Order Differentials
d2y=f′′(x)⋅(dx)2d^2 y = f''(x) \cdot (dx)^2

The notation d2y/dx2d^2 y / dx^2 for the second derivative arises from dividing both sides by (dx)2(dx)^2:

Higher-Order Differentials
d2ydx2=d2y(dx)2=f′′(x)\frac{d^2 y}{dx^2} = \frac{d^2 y}{(dx)^2} = f''(x)

This explains the Leibniz notation for higher derivatives. The superscript on d2yd^2 y counts the number of times the differential operator dd has been applied. The square on dx2dx^2 means (dx)2(dx)^2—the differential dxdx appearing as a factor twice—not the differential d(x2)d(x^2).

Higher-order differentials extend the approximation. The second-order estimate of the change in yy is

Higher-Order Differentials
Δy≈f′(x) dx+12f′′(x)(dx)2\Delta y \approx f'(x)\,dx + \frac{1}{2}f''(x)(dx)^2

Fact: Einstein's energy contains 12mv2\frac{1}{2}mv^2
In relativity a body's energy is E(v)=mc21−v2/c2E(v) = \frac{mc^2}{\sqrt{1 - v^2/c^2}}, with E′(0)=0E'(0) = 0 and E′′(0)=mE''(0) = m. The second-order estimate at v=0v = 0 gives E≈mc2+12mv2E \approx mc^2 + \frac{1}{2}mv^2: the rest energy plus Newton's kinetic energy.

This is the beginning of the Taylor expansion written in differential notation: f(x+dx)≈f(x)+f′(x) dx+12f′′(x)(dx)2+⋯f(x + dx) \approx f(x) + f'(x)\,dx + \frac{1}{2}f''(x)(dx)^2 + \cdots. Each additional term uses a higher-order derivative and a higher power of dxdx, improving the approximation at the cost of more computation.

When f′(x)=0f'(x) = 0, the first term drops out and the second-order term is the whole estimate: Δy≈12f′′(x)(dx)2\Delta y \approx \frac{1}{2}f''(x)(dx)^2. The change then grows with the square of the step rather than with the step itself, and the flat tangent line, which predicts no change at all, misses it entirely.
Notation Meaning How it arises
d²y second differential of y; equals f''(x)·(dx)² applying the differential operator d twice with dx held constant
dx² (dx)² — the differential dx appearing as a factor twice NOT d(x²); just (dx)² = dx·dx
d²y / dx² second derivative f''(x) dividing d²y = f''(x)·(dx)² by (dx)²

Summary: What Differentials Are Good For


The single formula dy=f′(x) dxdy = f'(x)\,dx underlies every application of differentials covered above. The table below collects those applications side by side, pairing each with the formula it specializes to, a worked example from the page, and the situation where it earns its place over alternatives. Together, these capture the practical payoff of treating dxdx and dydy as independent quantities rather than parts of an unbreakable dy/dxdy/dx symbol.
Use Formula Example Where it shines
Linear approximation f(x + dx) ≈ f(x) + f'(x) dx √4.03 ≈ 2 + ¼(0.03) = 2.0075 quick estimates near a known value
Absolute error |dy| ≈ |f'(x)| · |dx| error in xⁿ is n·x^(n−1)·dx propagating a single measurement uncertainty
Relative error |dy|/|f(x)| ≈ |f'(x)/f(x)| · |dx| xⁿ multiplies relative error by |n| power-law uncertainty scaling
Multivariable propagation dz = (∂f/∂x) dx + (∂f/∂y) dy rectangle: dA = w dl + l dw combining errors from several inputs
Notation algebra dy and dx as independent quantities chain rule cancellation, ∫…dx substitution working symbolically with derivatives
Second-order refinement Δy ≈ f'(x) dx + ½f''(x)(dx)² first two Taylor terms improving accuracy beyond the tangent line

Common Pitfalls


Four mistakes cause most wrong answers when differentials are used for estimates and error bounds. Each is marked where it happens in the sections above; here each is worked through in full, with the wrong and the right working side by side.

Dropping the dx

The differential dydy is written down as the derivative alone, without the factor dxdx. The result no longer depends on the step, so it cannot describe a change.

Wrong working: for y=x3y = x^3, dy=3x2dy = 3x^2. At x=2x = 2 this gives dy=12dy = 12, for a step of 0.10.1 and for a step of 0.0010.001 alike.

Right working: dy=f′(x) dx=3x2 dxdy = f'(x)\,dx = 3x^2\,dx. At x=2x = 2 with dx=0.1dx = 0.1, dy=12(0.1)=1.2dy = 12(0.1) = 1.2. The actual change is Δy=2.13−23=9.261−8=1.261\Delta y = 2.1^3 - 2^3 = 9.261 - 8 = 1.261, close to 1.21.2 and nowhere near 1212.

Why it happens: the derivative is computed first and stands on its own in prime notation; the differential is the same expression with dxdx attached, and the factor is easy to leave off.

How to check: dydy must scale with dxdx. Halving the step should halve dydy; if the answer contains no dxdx, nothing changes, and the factor is missing.

Reporting the change as the value

In a linear approximation, the differential dy=f′(a) dxdy = f'(a)\,dx is computed and given as the approximate value of ff, although it is only the change from the known value f(a)f(a).

Wrong working: for 4.03\sqrt{4.03} with a=4a = 4 and dx=0.03dx = 0.03, dy=14(0.03)=0.0075dy = \frac{1}{4}(0.03) = 0.0075, so 4.03≈0.0075\sqrt{4.03} \approx 0.0075.

Right working: 4.03≈f(4)+f′(4) dx=2+0.0075=2.0075\sqrt{4.03} \approx f(4) + f'(4)\,dx = 2 + 0.0075 = 2.0075.

Why it happens: the differential is the step that takes the work, and once it is done the problem feels finished; the known value f(a)f(a) was found at the start and is forgotten by the end.

How to check: the estimate must be close to the known value f(a)f(a), because xx is close to aa. 4.03\sqrt{4.03} has to be a little more than 4=2\sqrt{4} = 2.

Doubling the absolute error

The power rule for errors, that xnx^n carries ∣n∣|n| times the relative error of xx, is applied to the absolute error, the ±\pm figure of the measurement.

Wrong working: x=10±0.1x = 10 \pm 0.1, so x2=100±2(0.1)=100±0.2x^2 = 100 \pm 2(0.1) = 100 \pm 0.2.

Right working: the relative error of xx is 0.110\frac{0.1}{10}, which is 1%. Squaring doubles it to 2%, and 2% of 100100 is 22, so x2=100±2x^2 = 100 \pm 2. The differential gives the same: ∣dy∣=2x ∣dx∣=2(10)(0.1)=2|dy| = 2x\,|dx| = 2(10)(0.1) = 2.

Why it happens: "squaring doubles the error" is remembered without the word relative, and the ±\pm figure is the error that is written down.

How to check: square the largest possible value. 10.12=102.0110.1^2 = 102.01, about 22 above 100100, not 0.20.2.

Adding the input errors unweighted

For a quantity that depends on several measurements, the input errors are added as they are, without the partial derivatives that turn each one into a change of the result.

Wrong working: for A=lwA = lw with l=10±0.1l = 10 \pm 0.1 and w=5±0.05w = 5 \pm 0.05, dA=0.1+0.05=0.15dA = 0.1 + 0.05 = 0.15, so A≈50±0.15A \approx 50 \pm 0.15.

Right working: dA=∂A∂l dl+∂A∂w dw=w dl+l dw=5(0.1)+10(0.05)=1.0dA = \frac{\partial A}{\partial l}\,dl + \frac{\partial A}{\partial w}\,dw = w\,dl + l\,dw = 5(0.1) + 10(0.05) = 1.0, so A≈50±1.0A \approx 50 \pm 1.0.

Why it happens: the errors in length and width are both lengths, so adding them looks natural. But an error dldl in the length adds or removes a strip of size w×dlw \times dl, so it changes the area by ww times as much.

How to check: compute the area at the largest values. (10.1)(5.05)=51.005(10.1)(5.05) = 51.005, about 11 above 5050, not 0.150.15.

Differentials FAQ

Does dx mean d times x?

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No — dx is a single symbol, not a product. The d is not a factor and cannot be cancelled or divided out on its own. The misreading is tempting because dx really does behave algebraically: substitution in integration rearranges it, and dy/dx genuinely becomes a quotient once differentials are defined. What gets rearranged is dx as a whole.Read more →

When is dy exactly equal to Δy?

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Only when f is linear. For f(x) = mx + b the tangent line is the function itself, so dy = m·dx matches the actual change f(x + dx) − f(x) for every increment, however large. For any curved function the two differ, and the gap Δy − dy is the approximation error, widening as dx grows.Read more →

How accurate is a linear approximation?

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Two things control it: how far you move from the base point, and how sharply the curve bends there. The error grows with the distance from the base point and with the size of f″ nearby, since f″ measures how fast the curve pulls away from its tangent. Approximating √4.03 from x = 4 agrees to four decimal places; a much larger step would not be.Read more →

Why does squaring a measurement double its relative error?

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Because for f(x) = xⁿ the logarithmic derivative f′(x)/f(x) equals n/x, so the relative error in the output is |n| times the relative error in the input. Squaring gives n = 2, cubing gives n = 3. A 1% error in a measured radius becomes a 2% error in its square and a 3% error in its cube.Read more →

How do you get a better approximation than the tangent line?

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Add the second-order term: Δy ≈ f′(x)dx + ½f″(x)(dx)². The tangent line matches the curve's value and slope at the base point; the quadratic term also matches its bending, so it tracks the curve further out. Continuing this way — each term using one more derivative and one more power of dx — produces the Taylor expansion.Read more →