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Exponential Inequalities






When We Compare Powers

Exponential equations ask when two exponential expressions are equal. Exponential inequalities ask when one is larger than the other — and the answer hinges on a single property of the base that changes everything about how the inequality behaves.

Key Terms

Inequality Concepts

Exponential Inequality— direction depends on whether base is greater than or less than 11
Exponential Function— monotonicity determines direction
Base (of a Power)— a>1a > 1 preserves direction; 0<a<10 < a < 1 reverses it
Exponential Equation— same techniques, different operator

See All Algebra Definitions →


Key Principle: Base Determines Direction

The behavior of an exponential inequality depends entirely on whether the base is greater than 11 or between 00 and 11. This is the central idea on this page, and every solving method flows from it.

When a>1a > 1, the function axa^x is increasing — larger exponents produce larger values. So the inequality ax>aya^x > a^y holds exactly when x>yx > y. The direction of the inequality is preserved.

When 0<a<10 < a < 1, the function axa^x is decreasing — larger exponents produce smaller values. So the inequality ax>aya^x > a^y holds exactly when x<yx < y. The direction of the inequality flips.

The base a=1a = 1 is excluded because 1x=11^x = 1 for all xx — no inequality between distinct powers is possible.

This directional rule replaces the familiar "multiply or divide by a negative flips the inequality" from linear algebra. In exponential inequalities, it is not the sign of a multiplier but the size of the base that governs whether the inequality reverses.
Base condition Function ax What ax > ay means for x, y Example
a > 1 increasing x > y  (direction preserved) 2x > 8  ⟹  x > 3
0 < a < 1 decreasing x < y  (direction reversed) (1/3)x > 9  ⟹  x < −2
a = 1 constant: 1x = 1 for all x no inequality between distinct powers excluded from the framework

Solving Basic Exponential Inequalities

The simplest exponential inequalities are solved by expressing both sides as powers of the same base and then applying the directional rule.

The inequality 2x>82^x > 8 rewrites as 2x>232^x > 2^3. Since the base 22 is greater than 11, the function is increasing and the inequality preserves direction: x>3x > 3.

The inequality (13)x>9\left(\frac{1}{3}\right)^x > 9 requires more care. Rewrite 99 as a power of 13\frac{1}{3}: since 13−2=32=9\frac{1}{3}^{-2} = 3^2 = 9, the inequality becomes (13)x>(13)−2\left(\frac{1}{3}\right)^x > \left(\frac{1}{3}\right)^{-2}. The base 13\frac{1}{3} is between 00 and 11, so the function is decreasing and the inequality flips: x<−2x < -2.

The inequality 5x−1≤1255^{x-1} \leq 125 rewrites as 5x−1≤535^{x-1} \leq 5^3. Base greater than 11, direction preserved: x−1≤3x - 1 \leq 3, so x≤4x \leq 4.

The procedure is consistent: rewrite both sides with a common base, then read off the inequality between exponents — preserving direction if the base exceeds 11, reversing it if the base is a proper fraction.
(1/3)^x > 9 holds exactly for x < -2xy−3−2−112−2−11234567891011121314(1/3)ˣy = 9x = −2above 9 only for x < −2: the base 1/3 flips >A decreasing base reverses >: (1/3)ˣ > 9 means x < −2
The decreasing case

The section's (1/3)ˣ > 9, with 9 written as (1/3)⁻². The curve (1/3)ˣ falls from left to right, so it is above the level 9 only to the left of the crossing at x = −2. Comparing exponents therefore turns > into <: the solution is x < −2.

With 2ˣ > 8 the curve rises and the direction is kept: x > 3.

Inequalities Requiring Simplification

When the two sides of an inequality do not immediately share a base, the laws of exponents are needed to rewrite one or both sides before comparison.

The inequality 4x<324^x < 32 involves 4=224 = 2^2 and 32=2532 = 2^5. Rewriting: (22)x<25(2^2)^x < 2^5, so 22x<252^{2x} < 2^5. Base 2>12 > 1, direction preserved: 2x<52x < 5, giving x<52x < \frac{5}{2}.

The inequality 9x+1≥27x9^{x+1} \geq 27^x involves 9=329 = 3^2 and 27=3327 = 3^3. Rewriting: 32(x+1)≥33x3^{2(x+1)} \geq 3^{3x}, which gives 32x+2≥33x3^{2x+2} \geq 3^{3x}. Base 3>13 > 1, direction preserved: 2x+2≥3x2x + 2 \geq 3x, so 2≥x2 \geq x, meaning x≤2x \leq 2.

The inequality (14)x>(18)2\left(\frac{1}{4}\right)^x > \left(\frac{1}{8}\right)^2 requires converting both bases. Since 14=2−2\frac{1}{4} = 2^{-2} and 18=2−3\frac{1}{8} = 2^{-3}, the inequality becomes (2−2)x>(2−3)2(2^{-2})^x > (2^{-3})^2, or 2−2x>2−62^{-2x} > 2^{-6}. Base 2>12 > 1: −2x>−6-2x > -6, so x<3x < 3.

The algebraic manipulation happens before the directional rule is applied. Simplify first, compare second.
Inequality Common-base rewrite Exponent inequality  (base > 1: preserved) Solution
4x < 32 22x < 25 2x < 5 x < 5⁄2
9x+1 ≥ 27x 32x + 2 ≥ 33x 2x + 2 ≥ 3x x ≤ 2
(1/4)x > (1/8)2 2−2x > 2−6 −2x > −6 x < 3

Domain and Sign Considerations

Exponential expressions with positive bases carry a property that constrains the solution space: ax>0a^x > 0 for every real xx when a>0a > 0.

No real exponent can make a positive base produce zero or a negative result. The equation 2x=02^x = 0 has no solution. The inequality 3x<03^x < 0 has no solution. This fact is not just a technicality — it eliminates entire branches of potential answers.

The inequality 2x>−52^x > -5 is satisfied by every real xx, because 2x2^x is always positive and thus always greater than −5-5. No computation is needed once the sign property is recognized.

The inequality 2x<−12^x < -1 has no solution at all, for the same reason.

When negative exponents appear with variable bases, domain restrictions must be checked. The expression x−2>4x^{-2} > 4 requires x≠0x \neq 0, and the solution set must exclude zero regardless of what the algebra produces. Similarly, expressions involving rational exponents with even roots require the base to be non-negative.
2^x is always positive: 2^x > -5 always, 2^x < -1 neverxy−4−3−2−1123−6−5−4−3−2−112345678y = −1: 2ˣ < −1 never holdsy = −5: 2ˣ > −5 holds for every xy = 2ˣ2ˣ > 0 for every x: the curve never reaches the axisPositivity alone settles 2ˣ > −5 and 2ˣ < −1
Answers settled by positivity

The curve 2ˣ stays above the axis for every x. It therefore lies above any negative level, so 2ˣ > −5 holds for all real x, and it never comes down to a negative level, so 2ˣ < −1 has no solution. No computation is needed in either case.

Checking the sign first can finish an exponential inequality before any algebra.

Compound Inequalities

A compound exponential inequality places an exponential expression between two bounds, requiring the variable to satisfy both constraints simultaneously.

The inequality 14<2x<16\frac{1}{4} < 2^x < 16 sets lower and upper bounds on 2x2^x. Rewrite each bound as a power of 22: 2−2<2x<242^{-2} < 2^x < 2^4. Since the base 2>12 > 1 preserves direction, the solution is −2<x<4-2 < x < 4.

The inequality 127≤3x−1≤81\frac{1}{27} \leq 3^{x-1} \leq 81 rewrites as 3−3≤3x−1≤343^{-3} \leq 3^{x-1} \leq 3^4. Preserving direction: −3≤x−1≤4-3 \leq x - 1 \leq 4, so −2≤x≤5-2 \leq x \leq 5.

With a base between 00 and 11, both inequality directions flip. The inequality 19<(13)x<3\frac{1}{9} < \left(\frac{1}{3}\right)^x < 3 rewrites as (13)−2<(13)x<(13)−1\left(\frac{1}{3}\right)^{-2} < \left(\frac{1}{3}\right)^x < \left(\frac{1}{3}\right)^{-1}. Since 13<1\frac{1}{3} < 1, the function is decreasing: −2>x>−1-2 > x > -1, which reads as −1<x<−2-1 < x < -2 — but this is empty when written carelessly. Reversing properly: −2<x<−1-2 < x < -1. Care with the direction at each step prevents this kind of error.

Systems involving multiple exponential inequalities with different bases are handled by solving each inequality independently and then intersecting the solution sets.
1/4 < 2^x < 16 exactly for -2 < x < 4xy−3−2−112345−224681012141618y = 1/4y = 16(4, 16)solution −2 < x < 4: 2⁻² < 2ˣ < 2⁴1/4 < 2ˣ < 16 is 2⁻² < 2ˣ < 2⁴, so −2 < x < 4
Bounding an exponential on both sides

The section's 1/4 < 2ˣ < 16. Writing the bounds as 2⁻² and 2⁴ shows where the curve sits between the two dashed levels: exactly while x runs from −2 to 4. Base 2 is greater than 1, so both bounds keep their direction: −2 < x < 4.

With a base between 0 and 1, both bounds would flip and change places.

Summary of Cases

Across the techniques covered above, exponential inequalities fall into a small number of canonical types — each recognized by its shape and resolved by a characteristic move. The table below collects them, with the recognition cue, the solving move, a worked example, and the resulting solution.
Type How to recognize Solving move Example Solution
Basic one or both sides already a power of a common base match bases, then apply the base-direction rule 2x > 8  →  2x > 23 x > 3
Requires simplification bases differ but share a common prime use exponent laws to rewrite each side over a common base, then apply direction 4x < 32  →  22x < 25 x < 5⁄2
Sign shortcut ax compared to 0 or a negative number  (a > 0) recognize ax > 0 always; no computation needed 2x > −5  /  2x < −1 all real x  /  no solution
Compound exponential sandwiched between two bounds rewrite both bounds in the common base, solve both halves with the direction rule 1⁄4 < 2x < 16 −2 < x < 4

Exponential Inequalities FAQ

Does the rule about flipping when you multiply by a negative apply here?

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No, and expecting it is the usual source of sign errors. In linear inequalities the direction reverses when you multiply or divide by a negative number. In exponential inequalities the multiplier is irrelevant: what governs the direction is the size of the base. Above 11 the direction is preserved, between 00 and 11 it reverses.Read more →

Can an exponential inequality be true for every real number?

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Yes, and it can also be true for none. Since ax>0a^x > 0 for any positive base, 2x>−52^x > -5 holds for every real xx with no computation required, while 2x<−12^x < -1 and 2x=02^x = 0 have no solutions at all. Checking the sign of the other side first can settle the whole problem immediately.Read more →

Why is a base of 11 excluded?

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Because 1x=11^x = 1 for every exponent, so distinct powers of 11 are never distinct. There is nothing to compare: 1x1^x and 1y1^y are equal no matter what xx and yy are, which makes every strict inequality between them false and every non-strict one trivially true. The base must be positive and different from 11.Read more →

How do you flip a compound inequality with a fractional base?

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Reverse both comparisons and then rewrite the chain so it reads left to right. With 13\frac{1}{3} as the base, flipping −2<x<−1-2 < x < -1 carelessly produces −2>x>−1-2 > x > -1, which looks like the empty set once transcribed as −1<x<−2-1 < x < -2. Reorder the endpoints after reversing, and check that the smaller bound ends up on the left.Read more →