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Negative Exponents






What Happens Below Zero

The natural exponent definition — multiply the base by itself nn times — has no way to handle a0a^0 or a3a^{-3}. There is no such thing as multiplying a number by itself zero times or negative three times. Yet the laws of exponents demand that these expressions have values, and they leave no room for choice about what those values must be.



Motivation: Extending the Pattern

The quotient rule for natural exponents states that aman=amn\frac{a^m}{a^n} = a^{m-n} when m>nm > n. But the left side of that equation makes sense even when m=nm = n or m<nm < n — the fraction a3a3\frac{a^3}{a^3} and the fraction a2a5\frac{a^2}{a^5} are both perfectly well-defined as long as a0a \neq 0.

When m=nm = n, the left side gives anan=1\frac{a^n}{a^n} = 1, while the right side gives ann=a0a^{n-n} = a^0. If the rule is to hold, then a0a^0 must equal 11.

When m<nm < n, the left side produces a fraction. The expression a2a5=1a3\frac{a^2}{a^5} = \frac{1}{a^3} by cancellation, while the right side gives a25=a3a^{2-5} = a^{-3}. If the rule is to hold, then a3a^{-3} must equal 1a3\frac{1}{a^3}.

Neither definition is a choice. Both are forced by the requirement that the quotient rule — already established for natural exponents — continues to work when the exponent crosses zero into negative territory.

The Zero Exponent

For any nonzero aa:

a0=1a^0 = 1


The quotient rule provides one proof: a0=ann=anan=1a^0 = a^{n-n} = \frac{a^n}{a^n} = 1. But the same conclusion emerges from a purely numerical pattern. The powers of 33 descend by a factor of 33 at each step: 33=273^3 = 27, 32=93^2 = 9, 31=33^1 = 3. Continuing the pattern — dividing by 33 each time — gives 30=13^0 = 1. The same sequence works for any nonzero base: 50=15^0 = 1, (7)0=1(-7)^0 = 1, (0.01)0=1(0.01)^0 = 1.

The restriction a0a \neq 0 is essential. The expression 000^0 sits at the intersection of two conflicting patterns. Following a0=1a^0 = 1 suggests 00=10^0 = 1. Following 0n=00^n = 0 suggests 00=00^0 = 0. Since both patterns have equal claim and produce different answers, 000^0 is left undefined — or, in certain contexts, assigned a value by convention depending on the application, most commonly 11 in combinatorics and series.

Definition of Negative Exponents

For any nonzero aa and any natural number nn:

an=1ana^{-n} = \frac{1}{a^n}


A negative exponent produces the reciprocal of the corresponding positive power. The expression 23=123=182^{-3} = \frac{1}{2^3} = \frac{1}{8}. The expression 51=155^{-1} = \frac{1}{5}. The expression 104=110000=0.000110^{-4} = \frac{1}{10000} = 0.0001.

This definition is not arbitrary — it is the only one compatible with the product rule. The product a3a3a^3 \cdot a^{-3} must equal a3+(3)=a0=1a^{3+(-3)} = a^0 = 1. For that to hold, a3a^{-3} must be the value that multiplies with a3a^3 to give 11 — which is 1a3\frac{1}{a^3}.

When the base is itself a fraction, the reciprocal interpretation applies in full. The expression (13)2\left(\frac{1}{3}\right)^{-2} means the reciprocal of (13)2=19\left(\frac{1}{3}\right)^2 = \frac{1}{9}, which is 99. Equivalently, (13)2=32=9\left(\frac{1}{3}\right)^{-2} = 3^2 = 9. A negative exponent on a fraction flips it before raising to the positive power.

Double Negatives and Reciprocals

The reciprocal interpretation extends cleanly to fractions and nested negatives.

A negative exponent on a fraction inverts it:

(ab)n=(ba)n\left(\frac{a}{b}\right)^{-n} = \left(\frac{b}{a}\right)^n


The expression (25)3=(52)3=1258\left(\frac{2}{5}\right)^{-3} = \left(\frac{5}{2}\right)^3 = \frac{125}{8}. The negative exponent flips the fraction, and the positive exponent that remains is applied normally.

The case n=1n = 1 gives the simplest form of the reciprocal: a1=1aa^{-1} = \frac{1}{a}. This notation appears throughout algebra and beyond — a1a^{-1} is the standard way to write the multiplicative inverse of aa.

A negative exponent in the denominator moves the expression to the numerator. The fraction 1an\frac{1}{a^{-n}} equals ana^n, since taking the reciprocal of a reciprocal returns the original. Similarly, a2b3=b3a2\frac{a^{-2}}{b^{-3}} = \frac{b^3}{a^2} — each negative exponent crosses the fraction bar and becomes positive.

Verifying the Laws Still Hold

The definition an=1ana^{-n} = \frac{1}{a^n} was chosen to preserve the laws of exponents. Verification confirms that each rule carries through without exception.

The product rule: a2a3a^{-2} \cdot a^{-3} should equal a2+(3)=a5a^{-2+(-3)} = a^{-5}. Computing directly: 1a21a3=1a5=a5\frac{1}{a^2} \cdot \frac{1}{a^3} = \frac{1}{a^5} = a^{-5}. The rule holds.

Mixed signs: a3a5a^3 \cdot a^{-5} should equal a3+(5)=a2a^{3+(-5)} = a^{-2}. Computing directly: a31a5=a3a5=1a2=a2a^3 \cdot \frac{1}{a^5} = \frac{a^3}{a^5} = \frac{1}{a^2} = a^{-2}. The rule holds.

Power of a power: (a2)3(a^{-2})^3 should equal a(2)(3)=a6a^{(-2)(3)} = a^{-6}. Computing directly: (a2)3=a2a2a2=1a21a21a2=1a6=a6(a^{-2})^3 = a^{-2} \cdot a^{-2} \cdot a^{-2} = \frac{1}{a^2} \cdot \frac{1}{a^2} \cdot \frac{1}{a^2} = \frac{1}{a^6} = a^{-6}. The rule holds.

This is the central point. Negative exponents were not defined by intuition or analogy — they were defined as the unique values that make the algebraic machinery work. Every law that held for natural exponents continues to hold for all integers, because the definition was engineered to guarantee exactly that.

Worked Examples

Simplify 424^{-2}. Applying the definition: 42=142=1164^{-2} = \frac{1}{4^2} = \frac{1}{16}.

Simplify x3x7\frac{x^3}{x^7}. The quotient rule gives x37=x4=1x4x^{3-7} = x^{-4} = \frac{1}{x^4}. Both forms — x4x^{-4} and 1x4\frac{1}{x^4} — are correct; context determines which is preferred.

Simplify (2a3)2(2a^{-3})^2. Distribute the exponent: 22(a3)2=4a6=4a62^2 \cdot (a^{-3})^2 = 4a^{-6} = \frac{4}{a^6}.

Simplify a2b3a4b1\frac{a^{-2}b^3}{a^4b^{-1}}. Handle each variable separately. For aa: a24=a6a^{-2-4} = a^{-6}. For bb: b3(1)=b3+1=b4b^{3-(-1)} = b^{3+1} = b^4. The result is a6b4=b4a6a^{-6}b^4 = \frac{b^4}{a^6}.

Simplify (x1y2)3\left(\frac{x^{-1}}{y^2}\right)^{-3}. The negative exponent flips the fraction: (y2x1)3=(y2x1)3=(xy2)3=x3y6\left(\frac{y^2}{x^{-1}}\right)^3 = \left(\frac{y^2 \cdot x}{1}\right)^3 = (xy^2)^3 = x^3y^6.

In each case, the laws reduce the expression step by step. Negative exponents are not obstacles — they are instructions to take reciprocals, and they simplify by the same rules that govern every other exponent.