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Half Angle Trigonometric Identities


sin(α/2) = √( (1 − cos α) / 2 )
α70°
Bisected apex sceneOABMa = 1b = 1C = αα/2α/2cos(α/2)sin(α/2)sin(α/2)
Step 0 of 6

sin(α/2)

0.574

√((1 − cos α)/2)

0.574

Derivation
Press Play to step through the proof.
Function
Identity
Value
Source







Switching Between Functions

Six tabs at the top let you pick which half-angle identity to study: sin(α/2)\sin(\alpha/2), cos(α/2)\cos(\alpha/2), tan(α/2)\tan(\alpha/2), csc(α/2)\csc(\alpha/2), sec(α/2)\sec(\alpha/2), cot(α/2)\cot(\alpha/2).

How selection changes the view:
sin\sin and cos\cos open the geometric proof scene with a step-by-step animation.
tan\tan, csc\csc, sec\sec, and cot\cot open the derived identity card with the algebraic chain.
• The active tab is highlighted in deep blue.
• The URL updates with ?halfFn=...?halfFn=..., so links you copy preserve the selected function.

Clicking any row of the formula table at the bottom also jumps to that function.

Adjusting the Angle α

Each view exposes a slider for the base angle $\alpha$ in degrees, between 20°20° and 160°160°. The half angle is then α/2\alpha/2, ranging from 10°10° to 80°80°.

What changes as you slide:
• On geometric scenes, the SVG triangle resizes and the apex α\alpha updates immediately.
• The number readout shows the current value of α\alpha.
• The verification cards recompute both sides of the identity at the new α/2\alpha/2.

Sweep through several values to confirm each identity is not a coincidence at one angle but a true equality.

Playing Through a Geometric Proof

When sin\sin or cos\cos is active, an animated proof unfolds in six steps. A toolbar gives you control:

Reset — return to step 0 with a blank scene.
Prev / Next — step through one stage at a time.
Play / Pause — advance automatically.
Speed selector0.5×0.5\times, 1×1\times, 1.5×1.5\times, 2×2\times.

Each step adds one geometric element (radii, triangle fill, bisector, half-angles, leg labels, final metrics). The right-hand panel logs each step with its name and reasoning.

Reading the Geometric Scene

The SVG shows the unit circle with two radii OAOA and OBOB of length 11 meeting at the center OO with angle α\alpha between them.

Elements that appear across the steps:
Red arc at OO — the apex angle α\alpha.
Indigo chord ABAB — the base of the isosceles triangle.
Blue segment OMOM — the perpendicular bisector, equal to cos(α/2)\cos(\alpha/2).
Half-angles at OO — each labeled α/2\alpha/2 once the bisector is drawn.
Half-chord labelssin(α/2)\sin(\alpha/2) on segments MAMA and MBMB.

A small right-angle mark appears at MM when the perpendicular bisector becomes visible.

Working with Derived Identities

Selecting tan(α/2)\tan(\alpha/2), csc(α/2)\csc(\alpha/2), sec(α/2)\sec(\alpha/2), or cot(α/2)\cot(\alpha/2) opens a different card layout. Instead of a triangle, it shows the algebraic derivation as a chain of equations.

Layout of the derived card:
• A short intro explains which earlier identity the current one rests on.
Jump buttons link directly to the geometric proofs of the source identities.
• A multi-line derivation block shows each manipulation with a brief side note.
• Verification cards confirm both sides match numerically.

This split keeps the geometric ideas isolated to two functions and treats the other four as algebraic consequences.

Reading the Formula Table

A reference table beneath every scene lists all six identities at once:

Function column — the name of the trig function with α/2\alpha/2 argument.
Identity column — the right-hand side of the formula.
Value column — the numeric value at the current α/2\alpha/2.
Source column — labels each identity as geometric (sin\sin, cos\cos) or via X for derived ones.

Click any row to make that function active. The current row gets a deep-blue left border and tinted background.

Verifying Identities Numerically

Every scene includes two metric cards that compute both sides of the active identity at the current α\alpha.

Example for sin(α/2)\sin(\alpha/2):
• Left card shows sin(α/2)\sin(\alpha/2).
• Right card shows (1cosα)/2\sqrt{(1 - \cos\alpha)/2}.

The two numbers always match (within rounding to three decimals). Sweeping the slider while watching the cards is a fast empirical check that the identity holds for every α\alpha, not just the one in the picture. The formula table mirrors this across all six functions simultaneously.

Geometric Proofs: sin(α/2) and cos(α/2)

The two foundational identities are proved by drawing an isosceles triangle with two unit radii.

sin(α/2) — apply the law of cosines and equate with the squared chord:
AB2=22cosα=(2sin(α/2))2|AB|^2 = 2 - 2\cos\alpha = (2\sin(\alpha/2))^2

Solving gives sin(α/2)=(1cosα)/2\sin(\alpha/2) = \sqrt{(1 - \cos\alpha)/2}.

cos(α/2) — from Pythagoras in the half-triangle, cos2(α/2)=1sin2(α/2)\cos^2(\alpha/2) = 1 - \sin^2(\alpha/2). Substituting the sin half-angle identity:
cos(α/2)=(1+cosα)/2\cos(\alpha/2) = \sqrt{(1 + \cos\alpha)/2}


For full coverage and equivalent forms (including sign choices by quadrant), see the half angle identities theory page.

Derived Identities: tan(α/2), csc(α/2), sec(α/2), cot(α/2)

The four remaining identities follow directly from the first two:

tan(α/2) — from tan=sin/cos\tan = \sin/\cos applied to the half angle:
tan(α/2)=1cosα1+cosα\tan(\alpha/2) = \sqrt{\frac{1 - \cos\alpha}{1 + \cos\alpha}}


csc(α/2) — reciprocal of sin(α/2)\sin(\alpha/2):
csc(α/2)=21cosα\csc(\alpha/2) = \sqrt{\frac{2}{1 - \cos\alpha}}


sec(α/2) — reciprocal of cos(α/2)\cos(\alpha/2):
sec(α/2)=21+cosα\sec(\alpha/2) = \sqrt{\frac{2}{1 + \cos\alpha}}


cot(α/2) — reciprocal of tan(α/2)\tan(\alpha/2):
cot(α/2)=1+cosα1cosα\cot(\alpha/2) = \sqrt{\frac{1 + \cos\alpha}{1 - \cos\alpha}}


For step-by-step derivations and alternative forms, see the trigonometric identities page and the reciprocal identities page.

Why Half-Angle Identities Matter

Half-angle identities are essential whenever a problem asks for a trig function at an angle that is not on the unit circle but is half of one that is.

Exact-value computation — find sin15°\sin 15°, cos22.5°\cos 22.5°, tan75°\tan 75° from sin30°\sin 30°, cos45°\cos 45°, cos150°\cos 150°.
Integration — the Weierstrass substitution t=tan(α/2)t = \tan(\alpha/2) converts rational trig integrals into rational functions of tt.
Equation solving — reduce equations mixing sinα\sin\alpha and sin(α/2)\sin(\alpha/2) to single-argument form.
Geometry — apothems, chord lengths, and inscribed-polygon side lengths all use half-angle formulas.

For applications and worked examples, see the trigonometric identities applications page.

Related Concepts and Tools

Continue exploring with these connected resources:

Double Angle Identities — companion formulas for sin(2θ)\sin(2\theta), cos(2θ)\cos(2\theta), and beyond.
Pythagorean Identitiessin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1 and its companions, used in the cos half-angle proof.
Sum and Difference Identities — base relations from which double- and half-angle identities are derived.
Unit Circle — geometric setup for every identity in this tool.
Trigonometric Functions Graphs — see how sin\sin, cos\cos, tan\tan and their reciprocals evolve as the angle varies.
Triangle Explorer — interactive triangles with built-in law of sines and law of cosines.