When two sides of a right triangle are known, the acute angles can be determined. The process reverses the side-finding procedure: compute the ratio from the known sides, then apply the appropriate inverse trigonometric function to recover the angle.For example, in a right triangle with opposite side 5 and hypotenuse 13:sin(θ)=135⇒θ=arcsin(135)≈22.6° Given adjacent side 7 and opposite side 10:tan(θ)=710⇒θ=arctan(710)≈55.0° Once one acute angle is found, the other follows immediately: the two acute angles in a right triangle always sum to 90°. If θ≈22.6°, the other acute angle is approximately 90°−22.6°=67.4°.Any pair of sides is sufficient. If the hypotenuse and adjacent side are known, use arccos. If the opposite and adjacent sides are known, use arctan. If the opposite and hypotenuse are known, use arcsin. The Pythagorean theorem can also provide the third side first, opening up all three options — but this is an extra step that is rarely necessary.The solver patterns for the most common right-triangle problems — six scenarios distinguished by what is given and what is sought — collect into the reference table below, covering both side-finding (sections above) and angle-finding cases.
| Given |
Find |
Formula |
| angle θ + hypotenuse |
opposite side |
opposite = hypotenuse · sin θ |
| angle θ + hypotenuse |
adjacent side |
adjacent = hypotenuse · cos θ |
| angle θ + adjacent side |
opposite side |
opposite = adjacent · tan θ |
| opposite + hypotenuse |
angle θ |
θ = arcsin(opposite / hypotenuse) |
| adjacent + hypotenuse |
angle θ |
θ = arccos(adjacent / hypotenuse) |
| opposite + adjacent |
angle θ |
θ = arctan(opposite / adjacent) |
Opposite 5, hypotenuse 13: θ = 22.6°
This is the worked example: sin θ = 5/13, and the tool reports the angle that ratio belongs to, 22.6°, with its complement 67.4° at the other acute vertex. Recovering an angle from two sides is the ratio definition run backwards, which is what the inverse functions do. Enter any two sides and read the recovered angles on the triangle explorer.
Either acute angle can be recovered this way, and the two must always sum to 90°.