Quadraticf(x) = x²
f(x) = x²secant from (a, f(a)) to (b, f(b))tangent at c (parallel to secant)x = a, x = b
Mean Value Theorem on [a, b][a, b] = [-2, 2]
Secant slope
0
(f(b) − f(a)) / (b − a)
f'(c) at each c
0
matches secant slope
cc = 0→f'(c) = 0= secant slope 0
The secant slope from a to b equals f'(c) at every c — the tangent at c is parallel to the secant.MVT
Applieda=-2b=2tangent ∥ secant