The logarithm of a product, quotient, or power breaks apart in predictable ways. Each rule corresponds to an exponent law, inverted through the logarithmic lens. Mastering these rules enables expanding complex logarithmic expressions into simpler components and condensing sums or differences of logarithms into single expressions — both essential skills for solving equations.
The rule holds for any real exponent n, including fractions and negatives:
loga(x)=loga(x1/2)=21loga(x)
loga(x−3)=−3loga(x)
The Change of Base Formula
A logarithm in one base can be expressed using logarithms in any other base:
loga(x)=logb(a)logb(x)
This formula converts logarithms to a convenient base — typically 10 or e for calculator computation.
Derivation: Let loga(x)=y, so ay=x. Taking logb of both sides: logb(ay)=logb(x). By the power rule: y⋅logb(a)=logb(x). Solving for y: y=logb(a)logb(x).
Common applications:
log2(10)=log(2)log(10)=0.3011≈3.322
log5(7)=ln(5)ln(7)=1.6091.946≈1.209
A useful special case: loga(b)=logb(a)1. The logarithms are reciprocals when arguments and bases swap.
Expanding Logarithmic Expressions
A single logarithm with a compound argument can be written as a sum or difference of simpler logarithms, with exponents pulled out as coefficients. The product rule splits multiplication, the quotient rule splits division, and the power rule extracts exponents.
Example: Expand log2(z2x3y).
log2(z2x3y)=log2(x3y)−log2(z2)
=log2(x3)+log2(y)−log2(z2)
=3log2(x)+log2(y)−2log2(z)
Example: Expand ln(b3a).
ln(b3a)=ln(b3a)1/2=21ln(b3a)
=21(ln(a)−ln(b3))=21ln(a)−23ln(b)
Condensing Logarithmic Expressions
Multiple logarithms can be combined into a single logarithm by reversing the expansion process. Coefficients become exponents through the power rule, sums become products through the product rule, and differences become quotients through the quotient rule.
Example: Condense 2log(x)+log(y)−3log(z).
2log(x)+log(y)−3log(z)=log(x2)+log(y)−log(z3)
=log(x2y)−log(z3)=log(z3x2y)
Example: Condense 21ln(a+1)−ln(b)−ln(c).
21ln(a+1)−ln(b)−ln(c)=ln(a+1)1/2−ln(b)−ln(c)
=lna+1−ln(bc)=ln(bca+1)
Condensing is essential for solving equations where multiple logarithms must combine before applying the one-to-one property.
Common Errors
Several incorrect "rules" persistently appear. None of the following equalities hold:
loga(x+y)=loga(x)+loga(y)
The logarithm of a sum does not split. There is no simplification for loga(x+y).
loga(x−y)=loga(x)−loga(y)
The logarithm of a difference does not split either.
loga(x)⋅loga(y)=loga(xy)
Multiplying logarithms is not the same as the logarithm of a product.
loga(y)loga(x)=loga(yx)
Dividing logarithms is not the same as the logarithm of a quotient. However, note that loga(y)loga(x)=logy(x) by the change of base formula.
(loga(x))n=nloga(x)
Raising a logarithm to a power is not the same as multiplying by that power. The power rule applies to exponents inside the argument, not outside.