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Rules of Limits






Breaking Limits Into Pieces


Computing limits directly from definitions—chasing epsilons and deltas—is rigorous but impractical for everyday calculation. The power of limit rules lies in decomposition: break a complicated expression into simpler parts, find the limit of each part, then reassemble.

These rules reflect the algebraic structure of limits. The limit of a sum is the sum of the limits. The limit of a product is the product of the limits. Such properties hold because limits preserve algebraic operations, provided the component limits exist.

That final condition is crucial. Every rule listed here requires the individual limits to exist before the rule applies. When a limit yields an indeterminate form, the rules do not directly help—algebraic manipulation must come first.

Key Terms

Limit— the object these rules operate on
Indeterminate Form— signals that limit rules cannot be applied directly
Continuity— continuous functions allow limits to pass through compositions

See All Calculus Definitions →


Why Limit Rules Matter


Without rules, evaluating even simple limits would require returning to the definition each time. The definition asks whether f(x)f(x) can be made arbitrarily close to LL by taking xx sufficiently close to aa. Proving this directly for each new function is tedious.

Limit rules provide shortcuts. Once you establish that basic limits exist—constants, the identity function, standard functions—you can combine them using algebraic rules to handle complex expressions.

The rules also reveal structure. They show that limits behave like algebraic operations in many ways, which is why calculus meshes so naturally with algebra.

Limit of a Constant


For any constant cc:

Limit of a Constant
lim⁡x→ac=c\lim_{x \to a} c = c
Learn more about this formula: Limit of a Constant →

A constant function f(x)=cf(x) = c outputs the same value regardless of input. As xx approaches aa, the output remains cc. The limit is simply cc.

This rule seems trivial but serves as a foundation. Combined with other rules, it handles constant terms in any expression.

Limit of the Identity Function


For the identity function f(x)=xf(x) = x:

Limit of the Identity Function
lim⁡x→ax=a\lim_{x \to a} x = a
Learn more about this formula: Limit of the Identity Function →


As xx approaches aa, the value of xx approaches aa. This tautology provides the base case for handling any polynomial: every polynomial is built from constants and powers of xx, and this rule handles the linear term.

Sum and Difference Rules


If lim⁡x→af(x)=L\lim_{x \to a} f(x) = L and lim⁡x→ag(x)=M\lim_{x \to a} g(x) = M, then:

Sum and Difference Rule (Limits)
lim⁡x→a[f(x)±g(x)]=lim⁡x→af(x)±lim⁡x→ag(x)\lim_{x \to a} [f(x) \pm g(x)] = \lim_{x \to a} f(x) \pm \lim_{x \to a} g(x)
Learn more about this formula: Sum and Difference Rule (Limits) →


The limit of a sum is the sum of the limits. The limit of a difference is the difference of the limits.

Both component limits must exist. If either fails to exist, these rules do not apply. The indeterminate form ∞−∞\infty - \infty illustrates what can go wrong: two quantities both growing without bound may have a difference that converges, diverges, or oscillates.

Constant Multiple Rule


If lim⁡x→af(x)=L\lim_{x \to a} f(x) = L and cc is a constant:

Constant Multiple Rule (Limits)
lim⁡x→a[c⋅f(x)]=c⋅lim⁡x→af(x)\lim_{x \to a} [c \cdot f(x)] = c \cdot \lim_{x \to a} f(x)
Learn more about this formula: Constant Multiple Rule (Limits) →


Constants factor out of limits. This is a special case of the product rule where one factor is constant, but it appears frequently enough to state separately.

Scaling a function by a constant scales its limit by the same constant.

Product Rule


If lim⁡x→af(x)=L\lim_{x \to a} f(x) = L and lim⁡x→ag(x)=M\lim_{x \to a} g(x) = M, then:

Product Rule (Limits)
lim⁡x→a[f(x)⋅g(x)]=lim⁡x→af(x)⋅lim⁡x→ag(x)\lim_{x \to a} [f(x) \cdot g(x)] = \lim_{x \to a} f(x) \cdot \lim_{x \to a} g(x)
Learn more about this formula: Product Rule (Limits) →


The limit of a product is the product of the limits. This extends to any finite number of factors: if each factor has a limit, the product's limit equals the product of those limits.

The indeterminate form 0⋅∞0 \cdot \infty shows the rule's limitation. When one factor approaches 00 while the other grows without bound, the product's behavior depends on the relative rates—it might approach 00, ∞\infty, or any finite value.

Quotient Rule


If lim⁡x→af(x)=L\lim_{x \to a} f(x) = L and lim⁡x→ag(x)=M\lim_{x \to a} g(x) = M with M≠0M \neq 0, then:

Quotient Rule (Limits)
lim⁡x→af(x)g(x)=lim⁡x→af(x)lim⁡x→ag(x),lim⁡x→ag(x)≠0\lim_{x \to a} \frac{f(x)}{g(x)} = \frac{\lim_{x \to a} f(x)}{\lim_{x \to a} g(x)}, \quad \lim_{x \to a} g(x) \neq 0
Learn more about this formula: Quotient Rule (Limits) →


The limit of a quotient is the quotient of the limits, provided the denominator's limit is nonzero.

When M=0M = 0, the rule fails. If L≠0L \neq 0 and M=0M = 0, the limit is typically infinite (analyze the sign to determine +∞+\infty or −∞-\infty). If both L=0L = 0 and M=0M = 0, you have the indeterminate form 0/00/0, requiring further techniques.
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When the quotient rule applies
The limit of a quotient is the quotient of the limits, provided the denominator's limit is nonzero. When it is zero the rule fails, and the numerator's limit decides what happens instead.
Quotient rule
lim⁡x→af(x)g(x)\lim_{x \to a} \dfrac{f(x)}{g(x)}
split by the limits LL of ff and MM of gg
L=lim⁡x→af(x)L = \lim_{x \to a} f(x) and M=lim⁡x→ag(x)M = \lim_{x \to a} g(x)
✓
Case 1
M≠0M \neq 0
The rule applies
the limit of the quotient is the quotient of the limits
LM\dfrac{L}{M}
∞
Case 2
M=0, L≠0M = 0,\ L \neq 0
Typically infinite
analyze the sign from each side to decide between +∞+\infty and −∞-\infty
?
Case 3
M=0, L=0M = 0,\ L = 0
Indeterminate form 0/00/0
carries no information until the expression is rewritten; see further techniques
Takeaway
Check MM first. Only when M=0M = 0 does LL matter: a nonzero LL means the quotient grows without bound, and L=0L = 0 leaves the indeterminate form 0/00/0.
The quotient rule for limits: three outcomes·/calculus/limits/rulesLearn Math Class

Power Rule


If lim⁡x→af(x)=L\lim_{x \to a} f(x) = L and nn is a positive integer:

Power Rule (Limits)
lim⁡x→a[f(x)]n=[lim⁡x→af(x)]n\lim_{x \to a} [f(x)]^n = \left[\lim_{x \to a} f(x)\right]^n
Learn more about this formula: Power Rule (Limits) →


Repeated application of the product rule yields this result. The limit of a power is the power of the limit.

For rational exponents:

Power Rule
lim⁡x→a[f(x)]m/n=Lm/n\lim_{x \to a} [f(x)]^{m/n} = L^{m/n}

provided L>0L > 0 (or L≥0L \geq 0 when nn is odd). Root functions require care with domain restrictions.

Root Rule


If lim⁡x→af(x)=L\lim_{x \to a} f(x) = L and the nn-th root exists:

Root Rule (Limits)
lim⁡x→af(x)n=lim⁡x→af(x)n\lim_{x \to a} \sqrt[n]{f(x)} = \sqrt[n]{\lim_{x \to a} f(x)}
Learn more about this formula: Root Rule (Limits) →


For odd nn, this holds for all real LL. For even nn, the rule requires L≥0L \geq 0 and f(x)≥0f(x) \geq 0 near aa.

This is the power rule with exponent 1/n1/n. The limit of a root is the root of the limit, provided the root is defined.

Absolute Value Rule


If lim⁡x→af(x)=L\lim_{x \to a} f(x) = L, then:

Absolute Value Rule (Limits)
lim⁡x→a∣f(x)∣=∣lim⁡x→af(x)∣\lim_{x \to a} |f(x)| = \left|\lim_{x \to a} f(x)\right|
Learn more about this formula: Absolute Value Rule (Limits) →


The limit of an absolute value is the absolute value of the limit.

The converse does not hold: lim⁡x→a∣f(x)∣\lim_{x \to a} |f(x)| may exist even when lim⁡x→af(x)\lim_{x \to a} f(x) does not. For example, ∣(−1)n∣|(-1)^n| equals 11 for all nn, but (−1)n(-1)^n has no limit as n→∞n \to \infty.

Limits of Polynomials


For any polynomial p(x)=anxn+an−1xn−1+⋯+a1x+a0p(x) = a_n x^n + a_{n-1} x^{n-1} + \cdots + a_1 x + a_0:

Limit of a Polynomial
lim⁡x→ap(x)=p(a)\lim_{x \to a} p(x) = p(a)
Learn more about this formula: Limit of a Polynomial →


Direct substitution always works for polynomials. This follows from applying the sum, constant multiple, and power rules to each term.

Polynomials are continuous everywhere, so the limit at any point equals the function value at that point.

Limits of Rational Functions


For a rational function r(x)=p(x)q(x)r(x) = \dfrac{p(x)}{q(x)} where pp and qq are polynomials:

Limit of a Rational Function
lim⁡x→ap(x)q(x)=p(a)q(a),q(a)≠0\lim_{x \to a} \frac{p(x)}{q(x)} = \frac{p(a)}{q(a)}, \quad q(a) \neq 0
Learn more about this formula: Limit of a Rational Function →


When the denominator is nonzero at aa, substitute directly. When q(a)=0q(a) = 0, the quotient rule fails and other techniques are needed.

If q(a)=0q(a) = 0 but p(a)≠0p(a) \neq 0, the limit is infinite. If both p(a)=0p(a) = 0 and q(a)=0q(a) = 0, factor and cancel the common root before substituting.
Function class at x = a limx → a Status
Polynomial p(x) p(a) direct substitution always works (continuous everywhere)
Rational p(x)/q(x),  q(a) ≠ 0 p(a) / q(a) direct substitution works
Rational p(x)/q(x),  q(a) = 0,  p(a) ≠ 0 ±∞ limit is infinite; analyze sign near a to determine + or −
Rational p(x)/q(x),  p(a) = q(a) = 0 0 / 0 indeterminate factor and cancel the common root, then re-evaluate — see evaluating limits

Composition Rule


If lim⁡x→ag(x)=L\lim_{x \to a} g(x) = L and ff is continuous at LL, then:

Composition Rule (Limits)
lim⁡x→af(g(x))=f(lim⁡x→ag(x))if f continuous at lim⁡x→ag(x)\lim_{x \to a} f(g(x)) = f\left(\lim_{x \to a} g(x)\right) \quad \text{if } f \text{ continuous at } \lim_{x \to a} g(x)
Learn more about this formula: Composition Rule (Limits) →


The limit passes through continuous functions. You first find the limit of the inner function, then apply the outer function to that limit.

Continuity of ff at LL is essential. Without it, the behavior of ff near LL might not match f(L)f(L), and the rule fails.

The Squeeze Theorem


Suppose g(x)≤f(x)≤h(x)g(x) \leq f(x) \leq h(x) for all xx near aa (except possibly at aa itself). If:

The Squeeze Theorem
lim⁡x→ag(x)=Landlim⁡x→ah(x)=L\lim_{x \to a} g(x) = L \quad \text{and} \quad \lim_{x \to a} h(x) = L

then:

The Squeeze Theorem
lim⁡x→af(x)=L\lim_{x \to a} f(x) = L

Squeeze Theorem
g(x)≤f(x)≤h(x) near a,  lim⁡x→ag(x)=lim⁡x→ah(x)=L  ⟹  lim⁡x→af(x)=Lg(x) \leq f(x) \leq h(x) \text{ near } a, \; \lim_{x \to a} g(x) = \lim_{x \to a} h(x) = L \implies \lim_{x \to a} f(x) = L
Learn more about this formula: Squeeze Theorem →


The function ff is trapped between two functions that converge to the same limit. It has nowhere to go but LL.

This theorem proves the special limit lim⁡x→0sin⁡xx=1\lim_{x \to 0} \dfrac{\sin x}{x} = 1 through a geometric argument that bounds sin⁡xx\dfrac{\sin x}{x} between cos⁡x\cos x and 11 near zero.
x^2 sin(1/x) oscillates between -x^2 and x^2; both bounds go to 0 at 0, so the squeezed function does tooxyh(x) = x²g(x) = −x²f(x) = x² sin(1/x)trapped: f → 0 as x → 0The bounds close in on 0, and the trapped function has to follow
The squeeze theorem in action

f(x) = x² sin(1/x) oscillates faster and faster as x approaches 0, so no limit rule can be applied to sin(1/x) directly. But sin(1/x) always lies between −1 and 1, so the graph of f is trapped between g(x) = −x² and h(x) = x². Both bounds go to 0 at x = 0, the band pinches shut, and the trapped function has no choice: its limit at 0 is 0 as well.

Without the factor x² the band would stay between −1 and 1 and the squeeze would fail.

When Rules Fail


    Every rule requires component limits to exist. When they don't, the rule cannot be applied directly.

    Indeterminate forms signal this breakdown:

  • 00\dfrac{0}{0} — quotient rule fails
  • ∞∞\dfrac{\infty}{\infty} — quotient rule fails
  • 0⋅∞0 \cdot \infty — product rule fails
  • ∞−∞\infty - \infty — difference rule fails
  • 000^0, 1∞1^\infty, ∞0\infty^0 — power rule fails

  • These forms require transformation before rules apply. Factor and cancel, rationalize, rewrite in equivalent forms—the goal is to eliminate the indeterminate form so that limit rules can finish the computation.

    The evaluating limits page covers techniques for resolving these cases.
Indeterminate form Arising from Rule that fails
0 / 0 f → 0 divided by g → 0 quotient rule (denominator limit is 0)
∞ / ∞ f → ∞ divided by g → ∞ quotient rule (neither side is finite)
0 · ∞ f → 0 multiplied by g → ∞ product rule (one factor not finite)
∞ − ∞ f → ∞ minus g → ∞ difference rule (both quantities not finite)
00 f → 0 raised to g → 0 power rule (subtle interaction between base and exponent)
1∞ f → 1 raised to g → ∞ power rule (the limit of 1 + 1/x to the x is e, not 1)
∞0 f → ∞ raised to g → 0 power rule (subtle interaction between base and exponent)

Summary: Master Reference of Limit Rules


The rules above split into three families: the basic facts (constant, identity), the algebraic combination rules (sum/difference, constant multiple, product, quotient, power, root, absolute value), and the advanced rules (composition, Squeeze Theorem). The table below collects all eleven in one place with each rule's precise conditions, since the conditions — not the formulas — are what distinguish correct application from a misuse that produces a wrong answer.
Rule Statement Conditions
Constant limx → a c = c always — no conditions
Identity limx → a x = a always — no conditions
Sum / Difference lim (f ± g) = L ± M both component limits exist
Constant multiple lim (c · f) = c · L the limit of f exists; c any real constant
Product lim (f · g) = L · M both component limits exist
Quotient lim (f / g) = L / M both component limits exist AND M ≠ 0
Power lim fn = Ln n positive integer; rational n requires L > 0 (or L ≥ 0 when denominator is odd)
Root lim  n√f = n√L odd n: all L; even n: L ≥ 0 and f ≥ 0 near a
Absolute value lim |f| = |L| the limit of f exists (converse does not hold)
Composition lim f(g(x)) = f(L) lim g(x) = L AND f is continuous at L
Squeeze Theorem lim f = L g(x) ≤ f(x) ≤ h(x) near a, with lim g = lim h = L

Limit Rules FAQ

What happens if the limit of the denominator is zero?

+
The quotient rule no longer applies, and two cases split apart. If the numerator approaches a nonzero value while the denominator approaches zero, the quotient grows without bound — check the sign from each side to decide between +∞ and −∞. If both approach zero, the result is the indeterminate form 0/0, which carries no information until the expression is rewritten. See evaluating limits.Read more →

Why does the composition rule require continuity?

+
Because the rule moves the limit inside the outer function, and that step is only valid when the behavior of f near L matches f(L) — which is exactly what continuity at L guarantees. Without it, g(x) can approach L while f(g(x)) approaches something other than f(L). A hole or jump in f at L breaks the substitution even though the inner limit exists.Read more →

When should you use the Squeeze Theorem?

+
Use it when a limit resists direct evaluation but the function can be trapped between two simpler ones sharing the same limit. If g(x) ≤ f(x) ≤ h(x) near a, and both g and h approach L, then f has nowhere to go but L. The classic application proves the special limit sin(x)/x → 1 by bounding it between cos x and 1.Read more →